x-1 is one of the factors of p(x) = x^3 - 3x^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the factor of the polynomial $p(x) = x^3 - 3x^2 + 7x - 5$,we use the Factor Theorem.According to the Factor Theorem,$(x-a)$ is a factor of

Vedclass · Accepted Answer

$x-1$

Vedclass · Answer

(D) To find the factor of the polynomial $p(x) = x^3 - 3x^2 + 7x - 5$,we use the Factor Theorem.According to the Factor Theorem,$(x-a)$ is a factor of $p(x)$ if $p(a) = 0$.Let us test the given options:For option $D$,$x-1 = 0$ implies $x = 1$.$p(1) = (1)^3 - 3(1)^2 + 7(1) - 5$$p(1) = 1 - 3 + 7 - 5$$p(1) = 8 - 8 = 0$.Since $p(1) = 0$,$(x-1)$ is a factor of the polynomial $p(x)$.

$x-1$ is one of the factors of $p(x) = x^3 - 3x^2 + 7x - 5$. Which of the following is a factor of $p(x) = x^3 - 3x^2 + 7x - 5$?

Similar Questions

Expand $\left(\frac{2x}{3} + \frac{3y}{4}\right)^{2}$.

Using long division,find the quotient and the remainder when the polynomial $x^{4}+1$ is divided by $x+1$.

Multiply $x^{2}+4 y^{2}+z^{2}+2 x y+x z-2 y z$ by $(-z+x-2 y)$.

Factorise the following expression: $27 x^{3}-64-108 x^{2}+144 x$

Show that $2x - 3$ is a factor of $x + 2x^3 - 9x^2 + 12$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module