x-1 is one of the factors of p(x) = x^3 - 3x^ | vedclass

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(D) To find the factor of the polynomial $p(x) = x^3 - 3x^2 + 7x - 5$,we use the Factor Theorem.According to the Factor Theorem,$(x-a)$ is a factor of

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$x-1$

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(D) To find the factor of the polynomial $p(x) = x^3 - 3x^2 + 7x - 5$,we use the Factor Theorem.According to the Factor Theorem,$(x-a)$ is a factor of $p(x)$ if $p(a) = 0$.Let us test the given options:For option $D$,$x-1 = 0$ implies $x = 1$.$p(1) = (1)^3 - 3(1)^2 + 7(1) - 5$$p(1) = 1 - 3 + 7 - 5$$p(1) = 8 - 8 = 0$.Since $p(1) = 0$,$(x-1)$ is a factor of the polynomial $p(x)$.

$x-1$ is one of the factors of $p(x) = x^3 - 3x^2 + 7x - 5$. Which of the following is a factor of $p(x) = x^3 - 3x^2 + 7x - 5$?

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